Base | Representation |
---|---|
bin | 11000010011101000110110… |
… | …00101110111000111101001 |
3 | 21000020220012120101001122101 |
4 | 30021310123011313013221 |
5 | 24001221302031120131 |
6 | 305403110520453401 |
7 | 14154505412665435 |
oct | 1411643305670751 |
9 | 230226176331571 |
10 | 53451322520041 |
11 | 160386400a9086 |
12 | 5bb328391a261 |
13 | 23a9590622364 |
14 | d2b0b48d79c5 |
15 | 62a5d17cec61 |
hex | 309d1b1771e9 |
53451322520041 has 2 divisors, whose sum is σ = 53451322520042. Its totient is φ = 53451322520040.
The previous prime is 53451322520003. The next prime is 53451322520077. The reversal of 53451322520041 is 14002522315435.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52940103240025 + 511219280016 = 7275995^2 + 714996^2 .
It is a cyclic number.
It is not a de Polignac number, because 53451322520041 - 243 = 44655229497833 is a prime.
It is not a weakly prime, because it can be changed into another prime (53451322529041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26725661260020 + 26725661260021.
It is an arithmetic number, because the mean of its divisors is an integer number (26725661260021).
Almost surely, 253451322520041 is an apocalyptic number.
It is an amenable number.
53451322520041 is a deficient number, since it is larger than the sum of its proper divisors (1).
53451322520041 is an equidigital number, since it uses as much as digits as its factorization.
53451322520041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 53451322520041 its reverse (14002522315435), we get a palindrome (67453844835476).
The spelling of 53451322520041 in words is "fifty-three trillion, four hundred fifty-one billion, three hundred twenty-two million, five hundred twenty thousand, forty-one".
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