Base | Representation |
---|---|
bin | 110001110010000100… |
… | …101111101011010011 |
3 | 12002222021002210221212 |
4 | 301302010233223103 |
5 | 1333433041012120 |
6 | 40320045010335 |
7 | 3601424601602 |
oct | 616204575323 |
9 | 162867083855 |
10 | 53453454035 |
11 | 207400991a3 |
12 | a4395539ab |
13 | 506b390157 |
14 | 2831253a39 |
15 | 15ccb5a6c5 |
hex | c7212fad3 |
53453454035 has 4 divisors (see below), whose sum is σ = 64144144848. Its totient is φ = 42762763224.
The previous prime is 53453454013. The next prime is 53453454071. The reversal of 53453454035 is 53045435435.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53045435435 = 5 ⋅10609087087.
It is a cyclic number.
It is not a de Polignac number, because 53453454035 - 26 = 53453453971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53453453983 and 53453454001.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5345345399 + ... + 5345345408.
It is an arithmetic number, because the mean of its divisors is an integer number (16036036212).
Almost surely, 253453454035 is an apocalyptic number.
53453454035 is a deficient number, since it is larger than the sum of its proper divisors (10690690813).
53453454035 is a wasteful number, since it uses less digits than its factorization.
53453454035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10690690812.
The product of its (nonzero) digits is 1080000, while the sum is 41.
The spelling of 53453454035 in words is "fifty-three billion, four hundred fifty-three million, four hundred fifty-four thousand, thirty-five".
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