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53466024112013 is a prime number
BaseRepresentation
bin11000010100000100001110…
…10111111110111110001101
321000022022011011000022110202
430022002013113332332031
524001441404133041023
6305413541414543245
714155535630315552
oct1412020727767615
9230268134008422
1053466024112013
11160438a4833797
125bb60a7367b25
1323aaa943aa0c6
14d2baab240a29
1562ab922ec128
hex30a0875fef8d

53466024112013 has 2 divisors, whose sum is σ = 53466024112014. Its totient is φ = 53466024112012.

The previous prime is 53466024111989. The next prime is 53466024112019. The reversal of 53466024112013 is 31021142066435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39790132275364 + 13675891836649 = 6307942^2 + 3698093^2 .

It is a cyclic number.

It is not a de Polignac number, because 53466024112013 - 236 = 53397304635277 is a prime.

It is a super-3 number, since 3×534660241120133 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53466024112019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26733012056006 + 26733012056007.

It is an arithmetic number, because the mean of its divisors is an integer number (26733012056007).

Almost surely, 253466024112013 is an apocalyptic number.

It is an amenable number.

53466024112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

53466024112013 is an equidigital number, since it uses as much as digits as its factorization.

53466024112013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 53466024112013 its reverse (31021142066435), we get a palindrome (84487166178448).

The spelling of 53466024112013 in words is "fifty-three trillion, four hundred sixty-six billion, twenty-four million, one hundred twelve thousand, thirteen".