Base | Representation |
---|---|
bin | 111100110100110010101000… |
… | …0011110000001011111001111 |
3 | 2121011100112001112100211020011 |
4 | 1321221211100132001133033 |
5 | 1030111241234033034434 |
6 | 5133521151535134051 |
7 | 220460000250145435 |
oct | 17151452036013717 |
9 | 2534315045324204 |
10 | 535021131143119 |
11 | 145524207615a25 |
12 | 5000a81a374327 |
13 | 19c6c378a07b7a |
14 | 961923779cd55 |
15 | 41cc1da0ece64 |
hex | 1e699507817cf |
535021131143119 has 2 divisors, whose sum is σ = 535021131143120. Its totient is φ = 535021131143118.
The previous prime is 535021131143113. The next prime is 535021131143123. The reversal of 535021131143119 is 911341131120535.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-535021131143119 is a prime.
It is a super-2 number, since 2×5350211311431192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (535021131143113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267510565571559 + 267510565571560.
It is an arithmetic number, because the mean of its divisors is an integer number (267510565571560).
Almost surely, 2535021131143119 is an apocalyptic number.
535021131143119 is a deficient number, since it is larger than the sum of its proper divisors (1).
535021131143119 is an equidigital number, since it uses as much as digits as its factorization.
535021131143119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 40.
The spelling of 535021131143119 in words is "five hundred thirty-five trillion, twenty-one billion, one hundred thirty-one million, one hundred forty-three thousand, one hundred nineteen".
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