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535021131143119 is a prime number
BaseRepresentation
bin111100110100110010101000…
…0011110000001011111001111
32121011100112001112100211020011
41321221211100132001133033
51030111241234033034434
65133521151535134051
7220460000250145435
oct17151452036013717
92534315045324204
10535021131143119
11145524207615a25
125000a81a374327
1319c6c378a07b7a
14961923779cd55
1541cc1da0ece64
hex1e699507817cf

535021131143119 has 2 divisors, whose sum is σ = 535021131143120. Its totient is φ = 535021131143118.

The previous prime is 535021131143113. The next prime is 535021131143123. The reversal of 535021131143119 is 911341131120535.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-535021131143119 is a prime.

It is a super-2 number, since 2×5350211311431192 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (535021131143113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267510565571559 + 267510565571560.

It is an arithmetic number, because the mean of its divisors is an integer number (267510565571560).

Almost surely, 2535021131143119 is an apocalyptic number.

535021131143119 is a deficient number, since it is larger than the sum of its proper divisors (1).

535021131143119 is an equidigital number, since it uses as much as digits as its factorization.

535021131143119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 40.

The spelling of 535021131143119 in words is "five hundred thirty-five trillion, twenty-one billion, one hundred thirty-one million, one hundred forty-three thousand, one hundred nineteen".