Base | Representation |
---|---|
bin | 111100110101000001100101… |
… | …1001110110000111111110111 |
3 | 2121011110120222100000211221020 |
4 | 1321222003023032300333313 |
5 | 1030112303031402341210 |
6 | 5133544023335552223 |
7 | 220462215313604640 |
oct | 17152031316607767 |
9 | 2534416870024836 |
10 | 535053255512055 |
11 | 1455368a1a21865 |
12 | 50014aa482b673 |
13 | 19c723c82409b7 |
14 | 961aa03dd86c7 |
15 | 41cce6a4a4770 |
hex | 1e6a0cb3b0ff7 |
535053255512055 has 16 divisors (see below), whose sum is σ = 978383095793664. Its totient is φ = 244595773948320.
The previous prime is 535053255512033. The next prime is 535053255512159. The reversal of 535053255512055 is 550215552350535.
It is not a de Polignac number, because 535053255512055 - 210 = 535053255511031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 535053255511989 and 535053255512007.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2547872645191 + ... + 2547872645400.
It is an arithmetic number, because the mean of its divisors is an integer number (61148943487104).
Almost surely, 2535053255512055 is an apocalyptic number.
535053255512055 is a deficient number, since it is larger than the sum of its proper divisors (443329840281609).
535053255512055 is a wasteful number, since it uses less digits than its factorization.
535053255512055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5095745290606.
The product of its (nonzero) digits is 14062500, while the sum is 51.
The spelling of 535053255512055 in words is "five hundred thirty-five trillion, fifty-three billion, two hundred fifty-five million, five hundred twelve thousand, fifty-five".
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