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5352154014001 = 10152991623901
BaseRepresentation
bin100110111100010010100…
…1111010010000100110001
3200221122211211000120111111
41031320211033102010301
51200142202411422001
615214425015113321
71061452236330454
oct115704517220461
920848754016444
105352154014001
111783921457473
12725349672841
132ca923cb2b92
1414708d32549b
159434d90b851
hex4de253d2131

5352154014001 has 4 divisors (see below), whose sum is σ = 5405145638004. Its totient is φ = 5299162390000.

The previous prime is 5352154013989. The next prime is 5352154014007. The reversal of 5352154014001 is 1004104512535.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2186686775025 + 3165467238976 = 1478745^2 + 1779176^2 .

It is a cyclic number.

It is not a de Polignac number, because 5352154014001 - 29 = 5352154013489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5352154014007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26495811850 + ... + 26495812051.

It is an arithmetic number, because the mean of its divisors is an integer number (1351286409501).

Almost surely, 25352154014001 is an apocalyptic number.

It is an amenable number.

5352154014001 is a deficient number, since it is larger than the sum of its proper divisors (52991624003).

5352154014001 is a wasteful number, since it uses less digits than its factorization.

5352154014001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52991624002.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 5352154014001 its reverse (1004104512535), we get a palindrome (6356258526536).

The spelling of 5352154014001 in words is "five trillion, three hundred fifty-two billion, one hundred fifty-four million, fourteen thousand, one".

Divisors: 1 101 52991623901 5352154014001