Base | Representation |
---|---|
bin | 100110111100010111010… |
… | …1010011000110001111101 |
3 | 200221200020211111220100011 |
4 | 1031320232222120301331 |
5 | 1200143013400124201 |
6 | 15214452423503221 |
7 | 1061456166215335 |
oct | 115705652306175 |
9 | 20850224456304 |
10 | 5352312114301 |
11 | 17839a2721579 |
12 | 7253925b7b11 |
13 | 2ca94a989a59 |
14 | 1470a631c0c5 |
15 | 9435c73b151 |
hex | 4de2ea98c7d |
5352312114301 has 2 divisors, whose sum is σ = 5352312114302. Its totient is φ = 5352312114300.
The previous prime is 5352312114287. The next prime is 5352312114313. The reversal of 5352312114301 is 1034112132535.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5035652688676 + 316659425625 = 2244026^2 + 562725^2 .
It is a cyclic number.
It is not a de Polignac number, because 5352312114301 - 213 = 5352312106109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5352312114361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2676156057150 + 2676156057151.
It is an arithmetic number, because the mean of its divisors is an integer number (2676156057151).
Almost surely, 25352312114301 is an apocalyptic number.
It is an amenable number.
5352312114301 is a deficient number, since it is larger than the sum of its proper divisors (1).
5352312114301 is an equidigital number, since it uses as much as digits as its factorization.
5352312114301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 5352312114301 its reverse (1034112132535), we get a palindrome (6386424246836).
The spelling of 5352312114301 in words is "five trillion, three hundred fifty-two billion, three hundred twelve million, one hundred fourteen thousand, three hundred one".
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