Base | Representation |
---|---|
bin | 100110111100110101001… |
… | …1101000010111010100111 |
3 | 200221202211202002110120221 |
4 | 1031321222131002322213 |
5 | 1200202042200443311 |
6 | 15215140140305211 |
7 | 1061523066555613 |
oct | 115715235027247 |
9 | 20852752073527 |
10 | 5353315249831 |
11 | 17843679970aa |
12 | 725612542207 |
13 | 2caa7a754183 |
14 | 14715d644343 |
15 | 943ba83b671 |
hex | 4de6a742ea7 |
5353315249831 has 2 divisors, whose sum is σ = 5353315249832. Its totient is φ = 5353315249830.
The previous prime is 5353315249759. The next prime is 5353315249897. The reversal of 5353315249831 is 1389425133535.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5353315249831 - 27 = 5353315249703 is a prime.
It is a super-2 number, since 2×53533152498312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5353315249631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2676657624915 + 2676657624916.
It is an arithmetic number, because the mean of its divisors is an integer number (2676657624916).
Almost surely, 25353315249831 is an apocalyptic number.
5353315249831 is a deficient number, since it is larger than the sum of its proper divisors (1).
5353315249831 is an equidigital number, since it uses as much as digits as its factorization.
5353315249831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5832000, while the sum is 52.
The spelling of 5353315249831 in words is "five trillion, three hundred fifty-three billion, three hundred fifteen million, two hundred forty-nine thousand, eight hundred thirty-one".
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