Base | Representation |
---|---|
bin | 100110111101001001101… |
… | …0110001111011110100011 |
3 | 200221211121120002001120111 |
4 | 1031322103112033132203 |
5 | 1200204443320112011 |
6 | 15215332205352151 |
7 | 1061546100302554 |
oct | 115722326173643 |
9 | 20854546061514 |
10 | 5354001332131 |
11 | 178468a19a971 |
12 | 725784268657 |
13 | 2cab5992c72a |
14 | 1471c67d832b |
15 | 9440abb0121 |
hex | 4de9358f7a3 |
5354001332131 has 2 divisors, whose sum is σ = 5354001332132. Its totient is φ = 5354001332130.
The previous prime is 5354001332111. The next prime is 5354001332221. The reversal of 5354001332131 is 1312331004535.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5354001332131 - 27 = 5354001332003 is a prime.
It is a super-2 number, since 2×53540013321312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5354001332093 and 5354001332102.
It is not a weakly prime, because it can be changed into another prime (5354001332111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677000666065 + 2677000666066.
It is an arithmetic number, because the mean of its divisors is an integer number (2677000666066).
Almost surely, 25354001332131 is an apocalyptic number.
5354001332131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5354001332131 is an equidigital number, since it uses as much as digits as its factorization.
5354001332131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 5354001332131 its reverse (1312331004535), we get a palindrome (6666332336666).
The spelling of 5354001332131 in words is "five trillion, three hundred fifty-four billion, one million, three hundred thirty-two thousand, one hundred thirty-one".
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