Base | Representation |
---|---|
bin | 100110111101001001101… |
… | …0110001111100001000011 |
3 | 200221211121120002001210102 |
4 | 1031322103112033201003 |
5 | 1200204443320113131 |
6 | 15215332205353015 |
7 | 1061546100303203 |
oct | 115722326174103 |
9 | 20854546061712 |
10 | 5354001332291 |
11 | 178468a19aaa7 |
12 | 72578426876b |
13 | 2cab5992c821 |
14 | 1471c67d8403 |
15 | 9440abb01cb |
hex | 4de9358f843 |
5354001332291 has 2 divisors, whose sum is σ = 5354001332292. Its totient is φ = 5354001332290.
The previous prime is 5354001332243. The next prime is 5354001332293. The reversal of 5354001332291 is 1922331004535.
5354001332291 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5354001332291 - 218 = 5354001070147 is a prime.
Together with 5354001332293, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5354001332293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677000666145 + 2677000666146.
It is an arithmetic number, because the mean of its divisors is an integer number (2677000666146).
Almost surely, 25354001332291 is an apocalyptic number.
5354001332291 is a deficient number, since it is larger than the sum of its proper divisors (1).
5354001332291 is an equidigital number, since it uses as much as digits as its factorization.
5354001332291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 38.
The spelling of 5354001332291 in words is "five trillion, three hundred fifty-four billion, one million, three hundred thirty-two thousand, two hundred ninety-one".
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