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535410114113 = 776487159159
BaseRepresentation
bin1111100101010001110…
…11011111111001000001
31220011222122120212222102
413302220323133321001
532233004442122423
61045544120520145
753452650610550
oct7625073377101
91804878525872
10535410114113
11197080062316
1287923920055
133b648314814
141bcb1da7d97
15ddd96c3c28
hex7ca8edfe41

535410114113 has 4 divisors (see below), whose sum is σ = 611897273280. Its totient is φ = 458922954948.

The previous prime is 535410114097. The next prime is 535410114119. The reversal of 535410114113 is 311411014535.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 535410114113 - 24 = 535410114097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (535410114119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38243579573 + ... + 38243579586.

It is an arithmetic number, because the mean of its divisors is an integer number (152974318320).

Almost surely, 2535410114113 is an apocalyptic number.

It is an amenable number.

535410114113 is a deficient number, since it is larger than the sum of its proper divisors (76487159167).

535410114113 is an equidigital number, since it uses as much as digits as its factorization.

535410114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76487159166.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 535410114113 its reverse (311411014535), we get a palindrome (846821128648).

The spelling of 535410114113 in words is "five hundred thirty-five billion, four hundred ten million, one hundred fourteen thousand, one hundred thirteen".

Divisors: 1 7 76487159159 535410114113