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53542105054397 = 341428915681773
BaseRepresentation
bin11000010110010001111100…
…01001101111110010111101
321000120120112100201122002122
430023020332021233302331
524004213212343220042
6305512523053332325
714164201163543321
oct1413107611576275
9230516470648078
1053542105054397
1116073096510883
12600899a7970a5
1323b4cca5c07cb
14d316476d5981
1562cb466d37d2
hex30b23e26fcbd

53542105054397 has 4 divisors (see below), whose sum is σ = 53542124150460. Its totient is φ = 53542085958336.

The previous prime is 53542105054391. The next prime is 53542105054411. The reversal of 53542105054397 is 79345050124535.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13276214471716 + 40265890582681 = 3643654^2 + 6345541^2 .

It is a cyclic number.

It is not a de Polignac number, because 53542105054397 - 216 = 53542104988861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53542105054391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4426598 + ... + 11255175.

It is an arithmetic number, because the mean of its divisors is an integer number (13385531037615).

Almost surely, 253542105054397 is an apocalyptic number.

It is an amenable number.

53542105054397 is a deficient number, since it is larger than the sum of its proper divisors (19096063).

53542105054397 is a wasteful number, since it uses less digits than its factorization.

53542105054397 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19096062.

The product of its (nonzero) digits is 11340000, while the sum is 53.

The spelling of 53542105054397 in words is "fifty-three trillion, five hundred forty-two billion, one hundred five million, fifty-four thousand, three hundred ninety-seven".

Divisors: 1 3414289 15681773 53542105054397