Base | Representation |
---|---|
bin | 100110111101010101111… |
… | …1100011111011100011111 |
3 | 200221212200022121101012011 |
4 | 1031322223330133130133 |
5 | 1200211314441342231 |
6 | 15215441150452051 |
7 | 1061562241105456 |
oct | 115725374373437 |
9 | 20855608541164 |
10 | 5354414012191 |
11 | 1784881136572 |
12 | 72587a504027 |
13 | 2cabc429070a |
14 | 14722553db9d |
15 | 9443202a9b1 |
hex | 4deabf1f71f |
5354414012191 has 2 divisors, whose sum is σ = 5354414012192. Its totient is φ = 5354414012190.
The previous prime is 5354414012111. The next prime is 5354414012237. The reversal of 5354414012191 is 1912104144535.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5354414012191 - 27 = 5354414012063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5354414012111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677207006095 + 2677207006096.
It is an arithmetic number, because the mean of its divisors is an integer number (2677207006096).
Almost surely, 25354414012191 is an apocalyptic number.
5354414012191 is a deficient number, since it is larger than the sum of its proper divisors (1).
5354414012191 is an equidigital number, since it uses as much as digits as its factorization.
5354414012191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 5354414012191 in words is "five trillion, three hundred fifty-four billion, four hundred fourteen million, twelve thousand, one hundred ninety-one".
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