Base | Representation |
---|---|
bin | 111100111000010001101100… |
… | …0011011011000111110100011 |
3 | 2121020001022111102111002002021 |
4 | 1321300203120123120332203 |
5 | 1030142113303300233011 |
6 | 5134525212511202311 |
7 | 220536416003204065 |
oct | 17160433033307643 |
9 | 2536038442432067 |
10 | 535500153524131 |
11 | 145699381227824 |
12 | 50087625b16397 |
13 | 19ca55a8a78c33 |
14 | 96344ba937735 |
15 | 41d98c4255471 |
hex | 1e708d86d8fa3 |
535500153524131 has 4 divisors (see below), whose sum is σ = 535780961157672. Its totient is φ = 535219345890592.
The previous prime is 535500153524081. The next prime is 535500153524137. The reversal of 535500153524131 is 131425351005535.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 535500153524131 - 213 = 535500153515939 is a prime.
It is a super-2 number, since 2×5355001535241312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (535500153524137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140403813910 + ... + 140403817723.
It is an arithmetic number, because the mean of its divisors is an integer number (133945240289418).
Almost surely, 2535500153524131 is an apocalyptic number.
535500153524131 is a deficient number, since it is larger than the sum of its proper divisors (280807633541).
535500153524131 is a wasteful number, since it uses less digits than its factorization.
535500153524131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280807633540.
The product of its (nonzero) digits is 675000, while the sum is 43.
The spelling of 535500153524131 in words is "five hundred thirty-five trillion, five hundred billion, one hundred fifty-three million, five hundred twenty-four thousand, one hundred thirty-one".
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