131425351005535 has 4 divisors (see below), whose sum is σ = 157710421206648. Its totient is φ = 105140280804424.

The previous prime is 131425351005517. The next prime is 131425351005547. The reversal of 131425351005535 is 535500153524131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131425351005535 - 2⁹ = 131425351005023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131425351005491 and 131425351005500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13142535100549 + ... + 13142535100558.

It is an arithmetic number, because the mean of its divisors is an integer number (39427605301662).

Almost surely, 2^{131425351005535} is an apocalyptic number.

131425351005535 is a deficient number, since it is larger than the sum of its proper divisors (26285070201113).

131425351005535 is an equidigital number, since it uses as much as digits as its factorization.

131425351005535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26285070201112.

The product of its (nonzero) digits is 675000, while the sum is 43.

The spelling of 131425351005535 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, three hundred fifty-one million, five thousand, five hundred thirty-five".