Base | Representation |
---|---|
bin | 100110111101110011101… |
… | …1011111011101011001111 |
3 | 200221222020212201000000211 |
4 | 1031323213123323223033 |
5 | 1200220341000010111 |
6 | 15220124203303251 |
7 | 1061626050564634 |
oct | 115734733735317 |
9 | 20858225630024 |
10 | 5355412110031 |
11 | 1785243580215 |
12 | 725ab881ab27 |
13 | 2cb022cb2b59 |
14 | 1472bbd1418b |
15 | 9448e983521 |
hex | 4dee76fbacf |
5355412110031 has 2 divisors, whose sum is σ = 5355412110032. Its totient is φ = 5355412110030.
The previous prime is 5355412109947. The next prime is 5355412110053. The reversal of 5355412110031 is 1300112145535.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5355412110031 is a prime.
It is a super-2 number, since 2×53554121100312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5355412109975 and 5355412110002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5355412110431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677706055015 + 2677706055016.
It is an arithmetic number, because the mean of its divisors is an integer number (2677706055016).
Almost surely, 25355412110031 is an apocalyptic number.
5355412110031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5355412110031 is an equidigital number, since it uses as much as digits as its factorization.
5355412110031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 5355412110031 its reverse (1300112145535), we get a palindrome (6655524255566).
The spelling of 5355412110031 in words is "five trillion, three hundred fifty-five billion, four hundred twelve million, one hundred ten thousand, thirty-one".
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