Base | Representation |
---|---|
bin | 110001111000001000… |
… | …111100111000101101 |
3 | 12010020100121001122011 |
4 | 301320020330320231 |
5 | 1334140114020023 |
6 | 40334122121221 |
7 | 3604101600451 |
oct | 617010747055 |
9 | 163210531564 |
10 | 53555220013 |
11 | 20792586509 |
12 | a467650211 |
13 | 50864a16c9 |
14 | 2840984661 |
15 | 15d6a5d50d |
hex | c7823ce2d |
53555220013 has 4 divisors (see below), whose sum is σ = 53617566880. Its totient is φ = 53492873148.
The previous prime is 53555220001. The next prime is 53555220041. The reversal of 53555220013 is 31002255535.
53555220013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53555220013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53555226013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31172145 + ... + 31173862.
It is an arithmetic number, because the mean of its divisors is an integer number (13404391720).
Almost surely, 253555220013 is an apocalyptic number.
It is an amenable number.
53555220013 is a deficient number, since it is larger than the sum of its proper divisors (62346867).
53555220013 is an equidigital number, since it uses as much as digits as its factorization.
53555220013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62346866.
The product of its (nonzero) digits is 22500, while the sum is 31.
Adding to 53555220013 its reverse (31002255535), we get a palindrome (84557475548).
The spelling of 53555220013 in words is "fifty-three billion, five hundred fifty-five million, two hundred twenty thousand, thirteen".
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