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53560030147 = 134120002319
BaseRepresentation
bin110001111000011011…
…010011001111000011
312010020200122102220021
4301320123103033003
51334142331431042
640334413154311
73604160513251
oct617033231703
9163220572807
1053560030147
1120795271428
12a46918b997
135087496c40
1428414775d1
1515d71ad867
hexc786d33c3

53560030147 has 4 divisors (see below), whose sum is σ = 57680032480. Its totient is φ = 49440027816.

The previous prime is 53560030087. The next prime is 53560030169. The reversal of 53560030147 is 74103006535.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53560030147 - 235 = 19200291779 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53560730147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2060001147 + ... + 2060001172.

It is an arithmetic number, because the mean of its divisors is an integer number (14420008120).

Almost surely, 253560030147 is an apocalyptic number.

53560030147 is a deficient number, since it is larger than the sum of its proper divisors (4120002333).

53560030147 is a wasteful number, since it uses less digits than its factorization.

53560030147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4120002332.

The product of its (nonzero) digits is 37800, while the sum is 34.

The spelling of 53560030147 in words is "fifty-three billion, five hundred sixty million, thirty thousand, one hundred forty-seven".

Divisors: 1 13 4120002319 53560030147