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53610210113 is a prime number
BaseRepresentation
bin110001111011011010…
…101110001101000001
312010101012001211212112
4301323122232031001
51334243203210423
640343404505105
73605340160445
oct617332561501
9163335054775
1053610210113
1120810625379
12a481b4b195
1350949b6225
142847dba825
1515db7c1a78
hexc7b6ae341

53610210113 has 2 divisors, whose sum is σ = 53610210114. Its totient is φ = 53610210112.

The previous prime is 53610210103. The next prime is 53610210119. The reversal of 53610210113 is 31101201635.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27991966864 + 25618243249 = 167308^2 + 160057^2 .

It is a cyclic number.

It is not a de Polignac number, because 53610210113 - 214 = 53610193729 is a prime.

It is not a weakly prime, because it can be changed into another prime (53610210119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26805105056 + 26805105057.

It is an arithmetic number, because the mean of its divisors is an integer number (26805105057).

Almost surely, 253610210113 is an apocalyptic number.

It is an amenable number.

53610210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

53610210113 is an equidigital number, since it uses as much as digits as its factorization.

53610210113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 53610210113 its reverse (31101201635), we get a palindrome (84711411748).

The spelling of 53610210113 in words is "fifty-three billion, six hundred ten million, two hundred ten thousand, one hundred thirteen".