Base | Representation |
---|---|
bin | 110001111011100010… |
… | …010111010011010101 |
3 | 12010101022211121221121 |
4 | 301323202113103111 |
5 | 1334244211312321 |
6 | 40343515443541 |
7 | 3605363203222 |
oct | 617342272325 |
9 | 163338747847 |
10 | 53612213461 |
11 | 20811773534 |
12 | a4827565b1 |
13 | 5095238041 |
14 | 284837c949 |
15 | 15dba6a441 |
hex | c7b8974d5 |
53612213461 has 4 divisors (see below), whose sum is σ = 53612802124. Its totient is φ = 53611624800.
The previous prime is 53612213453. The next prime is 53612213467. The reversal of 53612213461 is 16431221635.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 26339342436 + 27272871025 = 162294^2 + 165145^2 .
It is a cyclic number.
It is not a de Polignac number, because 53612213461 - 23 = 53612213453 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53612213467) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125400 + ... + 350641.
It is an arithmetic number, because the mean of its divisors is an integer number (13403200531).
Almost surely, 253612213461 is an apocalyptic number.
It is an amenable number.
53612213461 is a deficient number, since it is larger than the sum of its proper divisors (588663).
53612213461 is a wasteful number, since it uses less digits than its factorization.
53612213461 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 588662.
The product of its digits is 25920, while the sum is 34.
The spelling of 53612213461 in words is "fifty-three billion, six hundred twelve million, two hundred thirteen thousand, four hundred sixty-one".
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