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53613219943 is a prime number
BaseRepresentation
bin110001111011100110…
…001101000001100111
312010101101201202120201
4301323212031001213
51334244441014233
640343553211331
73605404564453
oct617346150147
9163341652521
1053613219943
11208122a0738
12a482b60b47
1350954cb1aa
142848561663
1515dbbb877d
hexc7b98d067

53613219943 has 2 divisors, whose sum is σ = 53613219944. Its totient is φ = 53613219942.

The previous prime is 53613219931. The next prime is 53613219953. The reversal of 53613219943 is 34991231635.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53613219943 - 29 = 53613219431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53613219893 and 53613219902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53613219953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26806609971 + 26806609972.

It is an arithmetic number, because the mean of its divisors is an integer number (26806609972).

Almost surely, 253613219943 is an apocalyptic number.

53613219943 is a deficient number, since it is larger than the sum of its proper divisors (1).

53613219943 is an equidigital number, since it uses as much as digits as its factorization.

53613219943 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 524880, while the sum is 46.

The spelling of 53613219943 in words is "fifty-three billion, six hundred thirteen million, two hundred nineteen thousand, nine hundred forty-three".