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5362001103 = 311161160141
BaseRepresentation
bin1001111111001100…
…11010010011001111
3111211200112212201110
410333212122103033
541440133013403
62244022143103
7246606154164
oct47746322317
914750485643
105362001103
112301789878
121057881a93
13675b57424
1438c1b406b
15215b11103
hex13f99a4cf

5362001103 has 8 divisors (see below), whose sum is σ = 7150020016. Its totient is φ = 3574324800.

The previous prime is 5362001041. The next prime is 5362001107. The reversal of 5362001103 is 3011002635.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5362001103 - 212 = 5361997007 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5362001103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5362001107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46588 + ... + 113553.

It is an arithmetic number, because the mean of its divisors is an integer number (893752502).

Almost surely, 25362001103 is an apocalyptic number.

5362001103 is a deficient number, since it is larger than the sum of its proper divisors (1788018913).

5362001103 is a wasteful number, since it uses less digits than its factorization.

5362001103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171305.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 5362001103 is about 73225.6860876018. The cubic root of 5362001103 is about 1750.2857876664.

Adding to 5362001103 its reverse (3011002635), we get a palindrome (8373003738).

The spelling of 5362001103 in words is "five billion, three hundred sixty-two million, one thousand, one hundred three".

Divisors: 1 3 11161 33483 160141 480423 1787333701 5362001103