Base | Representation |
---|---|
bin | 100111000001011010010… |
… | …1101111011111000001111 |
3 | 200222201020020000202012001 |
4 | 1032002310231323320033 |
5 | 1200332213142013111 |
6 | 15223444141253131 |
7 | 1062321612254536 |
oct | 116026455737017 |
9 | 20881206022161 |
10 | 5363151126031 |
11 | 1788554aa2506 |
12 | 7274b85641a7 |
13 | 2cb987438b6a |
14 | 147813a8331d |
15 | 947940ca1c1 |
hex | 4e0b4b7be0f |
5363151126031 has 2 divisors, whose sum is σ = 5363151126032. Its totient is φ = 5363151126030.
The previous prime is 5363151125989. The next prime is 5363151126049. The reversal of 5363151126031 is 1306211513635.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5363151126031 - 221 = 5363149028879 is a prime.
It is a super-2 number, since 2×53631511260312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5363151126131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2681575563015 + 2681575563016.
It is an arithmetic number, because the mean of its divisors is an integer number (2681575563016).
Almost surely, 25363151126031 is an apocalyptic number.
5363151126031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5363151126031 is an equidigital number, since it uses as much as digits as its factorization.
5363151126031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 37.
Adding to 5363151126031 its reverse (1306211513635), we get a palindrome (6669362639666).
The spelling of 5363151126031 in words is "five trillion, three hundred sixty-three billion, one hundred fifty-one million, one hundred twenty-six thousand, thirty-one".
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