Base | Representation |
---|---|
bin | 11000011000111101001101… |
… | …10011000111101000110011 |
3 | 21000220100212111212001120121 |
4 | 30030132212303013220303 |
5 | 24012220021042344020 |
6 | 310023051132551111 |
7 | 14203634611550563 |
oct | 1414364663075063 |
9 | 230810774761517 |
10 | 53634055043635 |
11 | 160a9090920720 |
12 | 6022780622497 |
13 | 23c08923c9b71 |
14 | d35c8b590da3 |
15 | 630228d44baa |
hex | 30c7a6cc7a33 |
53634055043635 has 16 divisors (see below), whose sum is σ = 70216960810752. Its totient is φ = 39003748300000.
The previous prime is 53634055043609. The next prime is 53634055043677.
53634055043635 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53634055043635 - 213 = 53634055035443 is a prime.
It is a super-2 number, since 2×536340550436352 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34701649 + ... + 36214258.
It is an arithmetic number, because the mean of its divisors is an integer number (4388560050672).
Almost surely, 253634055043635 is an apocalyptic number.
53634055043635 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53634055043635 is a deficient number, since it is larger than the sum of its proper divisors (16582905767117).
53634055043635 is a wasteful number, since it uses less digits than its factorization.
53634055043635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70929674.
The product of its (nonzero) digits is 29160000, while the sum is 52.
The spelling of 53634055043635 in words is "fifty-three trillion, six hundred thirty-four billion, fifty-five million, forty-three thousand, six hundred thirty-five".
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