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536414144117 = 3474715437711
BaseRepresentation
bin1111100111001001100…
…01100100011001110101
31220021120121211220012212
413303210301210121311
532242034010102432
61050231504423205
753516561664665
oct7634461443165
91807517756185
10536414144117
11197545888985
1287b64017b05
133b778333107
141bd694841a5
15de478ee2b2
hex7ce4c64675

536414144117 has 4 divisors (see below), whose sum is σ = 536429616576. Its totient is φ = 536398671660.

The previous prime is 536414144113. The next prime is 536414144143. The reversal of 536414144117 is 711441414635.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 536414144117 - 22 = 536414144113 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (536414144113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7684109 + ... + 7753602.

It is an arithmetic number, because the mean of its divisors is an integer number (134107404144).

Almost surely, 2536414144117 is an apocalyptic number.

It is an amenable number.

536414144117 is a deficient number, since it is larger than the sum of its proper divisors (15472459).

536414144117 is a wasteful number, since it uses less digits than its factorization.

536414144117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15472458.

The product of its digits is 161280, while the sum is 41.

The spelling of 536414144117 in words is "five hundred thirty-six billion, four hundred fourteen million, one hundred forty-four thousand, one hundred seventeen".

Divisors: 1 34747 15437711 536414144117