Base | Representation |
---|---|
bin | 110001111101010001… |
… | …111001001011011001 |
3 | 12010110100212000012211 |
4 | 301331101321023121 |
5 | 1334324202401301 |
6 | 40350442235121 |
7 | 3606166542433 |
oct | 617521711331 |
9 | 163410760184 |
10 | 53641450201 |
11 | 20827222529 |
12 | a4904b5aa1 |
13 | 509b3037a1 |
14 | 284c1cd653 |
15 | 15de3e3051 |
hex | c7d4792d9 |
53641450201 has 2 divisors, whose sum is σ = 53641450202. Its totient is φ = 53641450200.
The previous prime is 53641450171. The next prime is 53641450223. The reversal of 53641450201 is 10205414635.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53406747801 + 234702400 = 231099^2 + 15320^2 .
It is a cyclic number.
It is not a de Polignac number, because 53641450201 - 215 = 53641417433 is a prime.
It is not a weakly prime, because it can be changed into another prime (53641454201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26820725100 + 26820725101.
It is an arithmetic number, because the mean of its divisors is an integer number (26820725101).
Almost surely, 253641450201 is an apocalyptic number.
It is an amenable number.
53641450201 is a deficient number, since it is larger than the sum of its proper divisors (1).
53641450201 is an equidigital number, since it uses as much as digits as its factorization.
53641450201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 53641450201 its reverse (10205414635), we get a palindrome (63846864836).
The spelling of 53641450201 in words is "fifty-three billion, six hundred forty-one million, four hundred fifty thousand, two hundred one".
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