Base | Representation |
---|---|
bin | 110001111101010010… |
… | …001101100001100101 |
3 | 12010110101000020112111 |
4 | 301331102031201211 |
5 | 1334324213033131 |
6 | 40350444121021 |
7 | 3606200340421 |
oct | 617522154145 |
9 | 163411006474 |
10 | 53641533541 |
11 | 2082727a102 |
12 | a490536171 |
13 | 509b3326bb |
14 | 284c211b81 |
15 | 15de40cab1 |
hex | c7d48d865 |
53641533541 has 2 divisors, whose sum is σ = 53641533542. Its totient is φ = 53641533540.
The previous prime is 53641533527. The next prime is 53641533577. The reversal of 53641533541 is 14533514635.
53641533541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49704473025 + 3937060516 = 222945^2 + 62746^2 .
It is a cyclic number.
It is not a de Polignac number, because 53641533541 - 25 = 53641533509 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53641533494 and 53641533503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53641536541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26820766770 + 26820766771.
It is an arithmetic number, because the mean of its divisors is an integer number (26820766771).
Almost surely, 253641533541 is an apocalyptic number.
It is an amenable number.
53641533541 is a deficient number, since it is larger than the sum of its proper divisors (1).
53641533541 is an equidigital number, since it uses as much as digits as its factorization.
53641533541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 324000, while the sum is 40.
The spelling of 53641533541 in words is "fifty-three billion, six hundred forty-one million, five hundred thirty-three thousand, five hundred forty-one".
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