Base | Representation |
---|---|
bin | 110001111101010101… |
… | …000000001101011001 |
3 | 12010110102101102111121 |
4 | 301331111000031121 |
5 | 1334324404443213 |
6 | 40350511525241 |
7 | 3606206506261 |
oct | 617525001531 |
9 | 163412342447 |
10 | 53642265433 |
11 | 20827729a79 |
12 | a490829821 |
13 | 509b52a883 |
14 | 284c3627a1 |
15 | 15de50488d |
hex | c7d540359 |
53642265433 has 2 divisors, whose sum is σ = 53642265434. Its totient is φ = 53642265432.
The previous prime is 53642265421. The next prime is 53642265503. The reversal of 53642265433 is 33456224635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50504921289 + 3137344144 = 224733^2 + 56012^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53642265433 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53642265433.
It is not a weakly prime, because it can be changed into another prime (53642260433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26821132716 + 26821132717.
It is an arithmetic number, because the mean of its divisors is an integer number (26821132717).
Almost surely, 253642265433 is an apocalyptic number.
It is an amenable number.
53642265433 is a deficient number, since it is larger than the sum of its proper divisors (1).
53642265433 is an equidigital number, since it uses as much as digits as its factorization.
53642265433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1555200, while the sum is 43.
The spelling of 53642265433 in words is "fifty-three billion, six hundred forty-two million, two hundred sixty-five thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •