Base | Representation |
---|---|
bin | 1111100111001011111… |
… | …01101111001011110101 |
3 | 1220021122000102022221020 |
4 | 13303211331233023311 |
5 | 32242104113024341 |
6 | 1050233500411353 |
7 | 53520223466061 |
oct | 7634575571365 |
9 | 1807560368836 |
10 | 536434111221 |
11 | 197556086518 |
12 | 87b6a846b59 |
13 | 3b77c504578 |
14 | 1bd6bda0aa1 |
15 | de49545566 |
hex | 7ce5f6f2f5 |
536434111221 has 16 divisors (see below), whose sum is σ = 750131673984. Its totient is φ = 340337501504.
The previous prime is 536434111181. The next prime is 536434111231. The reversal of 536434111221 is 122111434635.
It is a cyclic number.
It is not a de Polignac number, because 536434111221 - 222 = 536429916917 is a prime.
It is a super-2 number, since 2×5364341112212 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (536434111231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19718406 + ... + 19745591.
It is an arithmetic number, because the mean of its divisors is an integer number (46883229624).
Almost surely, 2536434111221 is an apocalyptic number.
It is an amenable number.
536434111221 is a deficient number, since it is larger than the sum of its proper divisors (213697562763).
536434111221 is a wasteful number, since it uses less digits than its factorization.
536434111221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39464220.
The product of its digits is 17280, while the sum is 33.
Adding to 536434111221 its reverse (122111434635), we get a palindrome (658545545856).
The spelling of 536434111221 in words is "five hundred thirty-six billion, four hundred thirty-four million, one hundred eleven thousand, two hundred twenty-one".
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