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53644124152693 is a prime number
BaseRepresentation
bin11000011001001111111101…
…11101101110001101110101
321000221022212020122210111201
430030213332331232031311
524012401131240341233
6310031434224532501
714204442255555634
oct1414477675561565
9230838766583451
1053644124152693
1116102388648358
126024710781131
1323c1808503469
14d3656498351b
15630617d0477d
hex30c9fef6e375

53644124152693 has 2 divisors, whose sum is σ = 53644124152694. Its totient is φ = 53644124152692.

The previous prime is 53644124152679. The next prime is 53644124152709. The reversal of 53644124152693 is 39625142144635.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32800900020849 + 20843224131844 = 5727207^2 + 4565438^2 .

It is a cyclic number.

It is not a de Polignac number, because 53644124152693 - 221 = 53644122055541 is a prime.

It is a super-2 number, since 2×536441241526932 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53644124152193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26822062076346 + 26822062076347.

It is an arithmetic number, because the mean of its divisors is an integer number (26822062076347).

Almost surely, 253644124152693 is an apocalyptic number.

It is an amenable number.

53644124152693 is a deficient number, since it is larger than the sum of its proper divisors (1).

53644124152693 is an equidigital number, since it uses as much as digits as its factorization.

53644124152693 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18662400, while the sum is 55.

The spelling of 53644124152693 in words is "fifty-three trillion, six hundred forty-four billion, one hundred twenty-four million, one hundred fifty-two thousand, six hundred ninety-three".