Base | Representation |
---|---|
bin | 1001111111011111… |
… | …01100010101101001 |
3 | 111211212010111102011 |
4 | 10333233230111221 |
5 | 41441243344111 |
6 | 2244150235521 |
7 | 246635640043 |
oct | 47757542551 |
9 | 14755114364 |
10 | 5364434281 |
11 | 23030a0968 |
12 | 1058655ba1 |
13 | 6764c9a8b |
14 | 38c648a93 |
15 | 215e42021 |
hex | 13fbec569 |
5364434281 has 2 divisors, whose sum is σ = 5364434282. Its totient is φ = 5364434280.
The previous prime is 5364434209. The next prime is 5364434321. The reversal of 5364434281 is 1824344635.
It is an a-pointer prime, because the next prime (5364434321) can be obtained adding 5364434281 to its sum of digits (40).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3777208681 + 1587225600 = 61459^2 + 39840^2 .
It is a cyclic number.
It is not a de Polignac number, because 5364434281 - 29 = 5364433769 is a prime.
It is a super-2 number, since 2×53644342812 = 57554310310335973922, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5364474281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2682217140 + 2682217141.
It is an arithmetic number, because the mean of its divisors is an integer number (2682217141).
Almost surely, 25364434281 is an apocalyptic number.
It is an amenable number.
5364434281 is a deficient number, since it is larger than the sum of its proper divisors (1).
5364434281 is an equidigital number, since it uses as much as digits as its factorization.
5364434281 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 276480, while the sum is 40.
The square root of 5364434281 is about 73242.2984415426. The cubic root of 5364434281 is about 1750.5504968531.
The spelling of 5364434281 in words is "five billion, three hundred sixty-four million, four hundred thirty-four thousand, two hundred eighty-one".
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