Base | Representation |
---|---|
bin | 1111100111001101001… |
… | …00000000111000111101 |
3 | 1220021122201022002222120 |
4 | 13303212210000320331 |
5 | 32242114200121323 |
6 | 1050234455433153 |
7 | 53520404666514 |
oct | 7634644007075 |
9 | 1807581262876 |
10 | 536444145213 |
11 | 19756080a179 |
12 | 87b720857b9 |
13 | 3b781608742 |
14 | 1bd6d45367b |
15 | de4a3785e3 |
hex | 7ce6900e3d |
536444145213 has 4 divisors (see below), whose sum is σ = 715258860288. Its totient is φ = 357629430140.
The previous prime is 536444145203. The next prime is 536444145229. The reversal of 536444145213 is 312541444635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 536444145213 - 230 = 535370403389 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (536444145203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89407357533 + ... + 89407357538.
It is an arithmetic number, because the mean of its divisors is an integer number (178814715072).
Almost surely, 2536444145213 is an apocalyptic number.
It is an amenable number.
536444145213 is a deficient number, since it is larger than the sum of its proper divisors (178814715075).
536444145213 is a wasteful number, since it uses less digits than its factorization.
536444145213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178814715074.
The product of its digits is 691200, while the sum is 42.
Adding to 536444145213 its reverse (312541444635), we get a palindrome (848985589848).
The spelling of 536444145213 in words is "five hundred thirty-six billion, four hundred forty-four million, one hundred forty-five thousand, two hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •