Base | Representation |
---|---|
bin | 110001111101101011… |
… | …011000011110011011 |
3 | 12010110211102110220200 |
4 | 301331223120132123 |
5 | 1334332410210440 |
6 | 40351241353243 |
7 | 3606310412043 |
oct | 617553303633 |
9 | 163424373820 |
10 | 53648131995 |
11 | 2082aa76677 |
12 | a492798823 |
13 | 509c802c03 |
14 | 284d04c723 |
15 | 15decb2c30 |
hex | c7dad879b |
53648131995 has 12 divisors (see below), whose sum is σ = 92990095536. Its totient is φ = 28612337040.
The previous prime is 53648131991. The next prime is 53648132033. The reversal of 53648131995 is 59913184635.
53648131995 is a `hidden beast` number, since 536 + 4 + 8 + 1 + 3 + 19 + 95 = 666.
It is not a de Polignac number, because 53648131995 - 22 = 53648131991 is a prime.
It is a super-3 number, since 3×536481319953 (a number of 33 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (53648131991) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 596090311 + ... + 596090400.
It is an arithmetic number, because the mean of its divisors is an integer number (7749174628).
Almost surely, 253648131995 is an apocalyptic number.
53648131995 is a deficient number, since it is larger than the sum of its proper divisors (39341963541).
53648131995 is a wasteful number, since it uses less digits than its factorization.
53648131995 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1192180722 (or 1192180719 counting only the distinct ones).
The product of its digits is 3499200, while the sum is 54.
The spelling of 53648131995 in words is "fifty-three billion, six hundred forty-eight million, one hundred thirty-one thousand, nine hundred ninety-five".
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