5365647399117 has 4 divisors (see below), whose sum is σ = 7154196532160. Its totient is φ = 3577098266076.

The previous prime is 5365647399097. The next prime is 5365647399127. The reversal of 5365647399117 is 7119937465635.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5365647399117 - 2¹² = 5365647395021 is a prime.

It is a super-3 number, since 3×5365647399117³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5365647399127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 894274566517 + ... + 894274566522.

It is an arithmetic number, because the mean of its divisors is an integer number (1788549133040).

Almost surely, 2^{5365647399117} is an apocalyptic number.

It is an amenable number.

5365647399117 is a deficient number, since it is larger than the sum of its proper divisors (1788549133043).

5365647399117 is a wasteful number, since it uses less digits than its factorization.

5365647399117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1788549133042.

The product of its digits is 128595600, while the sum is 66.

The spelling of 5365647399117 in words is "five trillion, three hundred sixty-five billion, six hundred forty-seven million, three hundred ninety-nine thousand, one hundred seventeen".