Base | Representation |
---|---|
bin | 110001111111010001… |
… | …011000101000010101 |
3 | 12010112200201222100221 |
4 | 301333101120220111 |
5 | 1334411231340232 |
6 | 40354034434341 |
7 | 3610053610204 |
oct | 617721305025 |
9 | 163480658327 |
10 | 53674871317 |
11 | 2084407a291 |
12 | a49b7329b1 |
13 | 50a52059b2 |
14 | 285280d23b |
15 | 15e22e5897 |
hex | c7f458a15 |
53674871317 has 2 divisors, whose sum is σ = 53674871318. Its totient is φ = 53674871316.
The previous prime is 53674871287. The next prime is 53674871339. The reversal of 53674871317 is 71317847635.
53674871317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36499720401 + 17175150916 = 191049^2 + 131054^2 .
It is a cyclic number.
It is not a de Polignac number, because 53674871317 - 215 = 53674838549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53674871377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26837435658 + 26837435659.
It is an arithmetic number, because the mean of its divisors is an integer number (26837435659).
Almost surely, 253674871317 is an apocalyptic number.
It is an amenable number.
53674871317 is a deficient number, since it is larger than the sum of its proper divisors (1).
53674871317 is an equidigital number, since it uses as much as digits as its factorization.
53674871317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2963520, while the sum is 52.
The spelling of 53674871317 in words is "fifty-three billion, six hundred seventy-four million, eight hundred seventy-one thousand, three hundred seventeen".
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