Base | Representation |
---|---|
bin | 11000011010010111011100… |
… | …01010110110110000100111 |
3 | 21001001222220112002220121022 |
4 | 30031023232022312300213 |
5 | 24014013223223313201 |
6 | 310101222042041355 |
7 | 14210301215256332 |
oct | 1415135612666047 |
9 | 231058815086538 |
10 | 53682497088551 |
11 | 1611768a119a91 |
12 | 603003b7a925b |
13 | 23c5312465376 |
14 | d38365013619 |
15 | 631611a4341b |
hex | 30d2ee2b6c27 |
53682497088551 has 2 divisors, whose sum is σ = 53682497088552. Its totient is φ = 53682497088550.
The previous prime is 53682497088527. The next prime is 53682497088617. The reversal of 53682497088551 is 15588079428635.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53682497088551 - 238 = 53407619181607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53682497088751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26841248544275 + 26841248544276.
It is an arithmetic number, because the mean of its divisors is an integer number (26841248544276).
It is a 1-persistent number, because it is pandigital, but 2⋅53682497088551 = 107364994177102 is not.
Almost surely, 253682497088551 is an apocalyptic number.
53682497088551 is a deficient number, since it is larger than the sum of its proper divisors (1).
53682497088551 is an equidigital number, since it uses as much as digits as its factorization.
53682497088551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 580608000, while the sum is 71.
The spelling of 53682497088551 in words is "fifty-three trillion, six hundred eighty-two billion, four hundred ninety-seven million, eighty-eight thousand, five hundred fifty-one".
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