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5368485791117 = 19282551883743
BaseRepresentation
bin100111000011111001010…
…1100000100010110001101
3201000020000000010210221102
41032013302230010112031
51200424124330303432
615230125345512445
71062601040210141
oct116076254042615
921006000123842
105368485791117
11178a842300329
12728547042725
132cc327711a17
14147b9c37d221
15949a75db962
hex4e1f2b0458d

5368485791117 has 4 divisors (see below), whose sum is σ = 5651037674880. Its totient is φ = 5085933907356.

The previous prime is 5368485791087. The next prime is 5368485791131. The reversal of 5368485791117 is 7111975848635.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5368485791117 - 210 = 5368485790093 is a prime.

It is a super-2 number, since 2×53684857911172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5368485791197) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141275941853 + ... + 141275941890.

It is an arithmetic number, because the mean of its divisors is an integer number (1412759418720).

Almost surely, 25368485791117 is an apocalyptic number.

It is an amenable number.

5368485791117 is a deficient number, since it is larger than the sum of its proper divisors (282551883763).

5368485791117 is a wasteful number, since it uses less digits than its factorization.

5368485791117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282551883762.

The product of its digits is 50803200, while the sum is 65.

The spelling of 5368485791117 in words is "five trillion, three hundred sixty-eight billion, four hundred eighty-five million, seven hundred ninety-one thousand, one hundred seventeen".

Divisors: 1 19 282551883743 5368485791117