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5370613477 is a prime number
BaseRepresentation
bin1010000000001110…
…10000111011100101
3111212021202102200021
411000013100323211
541444334112402
62244530515141
7250042314145
oct50007207345
914767672607
105370613477
112306631439
12105a735ab1
136778814c8
1438d3b6925
15216762d37
hex1401d0ee5

5370613477 has 2 divisors, whose sum is σ = 5370613478. Its totient is φ = 5370613476.

The previous prime is 5370613421. The next prime is 5370613499. The reversal of 5370613477 is 7743160735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5210818596 + 159794881 = 72186^2 + 12641^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5370613477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5370613877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2685306738 + 2685306739.

It is an arithmetic number, because the mean of its divisors is an integer number (2685306739).

Almost surely, 25370613477 is an apocalyptic number.

It is an amenable number.

5370613477 is a deficient number, since it is larger than the sum of its proper divisors (1).

5370613477 is an equidigital number, since it uses as much as digits as its factorization.

5370613477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 370440, while the sum is 43.

The square root of 5370613477 is about 73284.4695484657. The cubic root of 5370613477 is about 1751.2223815549. Note that the first 3 decimals are identical.

The spelling of 5370613477 in words is "five billion, three hundred seventy million, six hundred thirteen thousand, four hundred seventy-seven".