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53715500621677 is a prime number
BaseRepresentation
bin11000011011010100111010…
…10101010101111101101101
321001012011002121002002212001
430031222131111111331231
524020033321124343202
6310124321010212301
714212550115544456
oct1415523525257555
9231164077062761
1053715500621677
111612a6858169a4
126036510584091
1323c8471b7abab
14d39bb630412d
156323e41acd87
hex30da9d555f6d

53715500621677 has 2 divisors, whose sum is σ = 53715500621678. Its totient is φ = 53715500621676.

The previous prime is 53715500621663. The next prime is 53715500621707. The reversal of 53715500621677 is 77612600551735.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43578033065956 + 10137467555721 = 6601366^2 + 3183939^2 .

It is a cyclic number.

It is not a de Polignac number, because 53715500621677 - 215 = 53715500588909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53715500631677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857750310838 + 26857750310839.

It is an arithmetic number, because the mean of its divisors is an integer number (26857750310839).

Almost surely, 253715500621677 is an apocalyptic number.

It is an amenable number.

53715500621677 is a deficient number, since it is larger than the sum of its proper divisors (1).

53715500621677 is an equidigital number, since it uses as much as digits as its factorization.

53715500621677 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9261000, while the sum is 55.

The spelling of 53715500621677 in words is "fifty-three trillion, seven hundred fifteen billion, five hundred million, six hundred twenty-one thousand, six hundred seventy-seven".