Base | Representation |
---|---|
bin | 100111000110110101010… |
… | …1011000001110111010011 |
3 | 201000211021121200102112222 |
4 | 1032031222223001313103 |
5 | 1201030034200031034 |
6 | 15233051323211255 |
7 | 1063213254042536 |
oct | 116155253016723 |
9 | 21024247612488 |
10 | 5374793752019 |
11 | 1792489a5275a |
12 | 729807676b2b |
13 | 2ccac1534c73 |
14 | 1481da034a1d |
15 | 94c262a712e |
hex | 4e36aac1dd3 |
5374793752019 has 2 divisors, whose sum is σ = 5374793752020. Its totient is φ = 5374793752018.
The previous prime is 5374793751991. The next prime is 5374793752049. The reversal of 5374793752019 is 9102573974735.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5374793752019 is a prime.
It is a super-2 number, since 2×53747937520192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5374793752049) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2687396876009 + 2687396876010.
It is an arithmetic number, because the mean of its divisors is an integer number (2687396876010).
Almost surely, 25374793752019 is an apocalyptic number.
5374793752019 is a deficient number, since it is larger than the sum of its proper divisors (1).
5374793752019 is an equidigital number, since it uses as much as digits as its factorization.
5374793752019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50009400, while the sum is 62.
The spelling of 5374793752019 in words is "five trillion, three hundred seventy-four billion, seven hundred ninety-three million, seven hundred fifty-two thousand, nineteen".
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