5374794853 has 2 divisors, whose sum is σ = 5374794854. Its totient is φ = 5374794852.

The previous prime is 5374794833. The next prime is 5374794863. The reversal of 5374794853 is 3584974735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4332667329 + 1042127524 = 65823^2 + 32282^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5374794853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5374794794 and 5374794803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5374794833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2687397426 + 2687397427.

It is an arithmetic number, because the mean of its divisors is an integer number (2687397427).

Almost surely, 2^5374794853 is an apocalyptic number.

It is an amenable number.

5374794853 is a deficient number, since it is larger than the sum of its proper divisors (1).

5374794853 is an equidigital number, since it uses as much as digits as its factorization.

5374794853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12700800, while the sum is 55.

The square root of 5374794853 is about 73312.9923887983. The cubic root of 5374794853 is about 1751.6767442788.

The spelling of 5374794853 in words is "five billion, three hundred seventy-four million, seven hundred ninety-four thousand, eight hundred fifty-three".