Base | Representation |
---|---|
bin | 110010000100000011… |
… | …010000111000110111 |
3 | 12010202021121202121211 |
4 | 302010003100320313 |
5 | 1340042243240141 |
6 | 40410021222251 |
7 | 3612046301632 |
oct | 620403207067 |
9 | 163667552554 |
10 | 53755055671 |
11 | 20885366a49 |
12 | a502561987 |
13 | 50b89cbc65 |
14 | 285d322c19 |
15 | 15e9383d81 |
hex | c840d0e37 |
53755055671 has 2 divisors, whose sum is σ = 53755055672. Its totient is φ = 53755055670.
The previous prime is 53755055663. The next prime is 53755055677. The reversal of 53755055671 is 17655055735.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53755055671 - 23 = 53755055663 is a prime.
It is a super-3 number, since 3×537550556713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53755055677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26877527835 + 26877527836.
It is an arithmetic number, because the mean of its divisors is an integer number (26877527836).
Almost surely, 253755055671 is an apocalyptic number.
53755055671 is a deficient number, since it is larger than the sum of its proper divisors (1).
53755055671 is an equidigital number, since it uses as much as digits as its factorization.
53755055671 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2756250, while the sum is 49.
The spelling of 53755055671 in words is "fifty-three billion, seven hundred fifty-five million, fifty-five thousand, six hundred seventy-one".
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