Base | Representation |
---|---|
bin | 11000011100110001110000… |
… | …01111100011110111001111 |
3 | 21001100220202021120222010201 |
4 | 30032120320033203313033 |
5 | 24021342411104330404 |
6 | 310203242543314331 |
7 | 14216263231233532 |
oct | 1416307017436717 |
9 | 231326667528121 |
10 | 53765344214479 |
11 | 161498331709a7 |
12 | 6044100bab9a7 |
13 | 24000863b7581 |
14 | d3c383d5ca19 |
15 | 63385ee59ca4 |
hex | 30e6383e3dcf |
53765344214479 has 2 divisors, whose sum is σ = 53765344214480. Its totient is φ = 53765344214478.
The previous prime is 53765344214467. The next prime is 53765344214509. The reversal of 53765344214479 is 97441244356735.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53765344214479 - 233 = 53756754279887 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53765344214479.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53765344214419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26882672107239 + 26882672107240.
It is an arithmetic number, because the mean of its divisors is an integer number (26882672107240).
Almost surely, 253765344214479 is an apocalyptic number.
53765344214479 is a deficient number, since it is larger than the sum of its proper divisors (1).
53765344214479 is an equidigital number, since it uses as much as digits as its factorization.
53765344214479 is an evil number, because the sum of its binary digits is even.
The product of its digits is 304819200, while the sum is 64.
The spelling of 53765344214479 in words is "fifty-three trillion, seven hundred sixty-five billion, three hundred forty-four million, two hundred fourteen thousand, four hundred seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.092 sec. • engine limits •