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53787816141 = 317929272047
BaseRepresentation
bin110010000110000000…
…001111000011001101
312010211120021011112120
4302012000033003031
51340124140104031
640413151323153
73612624615333
oct620600170315
9163746234476
1053787816141
11208a1902414
12a5115204b9
1350c272c557
14286380db53
1515ec1a5a96
hexc8600f0cd

53787816141 has 4 divisors (see below), whose sum is σ = 71717088192. Its totient is φ = 35858544092.

The previous prime is 53787816139. The next prime is 53787816143. The reversal of 53787816141 is 14161878735.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (53787816139) and next prime (53787816143).

It is a cyclic number.

It is not a de Polignac number, because 53787816141 - 21 = 53787816139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53787816143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8964636021 + ... + 8964636026.

It is an arithmetic number, because the mean of its divisors is an integer number (17929272048).

Almost surely, 253787816141 is an apocalyptic number.

It is an amenable number.

53787816141 is a deficient number, since it is larger than the sum of its proper divisors (17929272051).

53787816141 is a wasteful number, since it uses less digits than its factorization.

53787816141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17929272050.

The product of its digits is 1128960, while the sum is 51.

The spelling of 53787816141 in words is "fifty-three billion, seven hundred eighty-seven million, eight hundred sixteen thousand, one hundred forty-one".

Divisors: 1 3 17929272047 53787816141