Base | Representation |
---|---|
bin | 110010000111100000… |
… | …011111100111100111 |
3 | 12010220022202011122200 |
4 | 302013200133213213 |
5 | 1340202120043311 |
6 | 40415452225543 |
7 | 3613352243052 |
oct | 620740374747 |
9 | 163808664580 |
10 | 53813049831 |
11 | 20905077902 |
12 | a519a6b2b3 |
13 | 50c7a25c28 |
14 | 2866cdba99 |
15 | 15ee4dc556 |
hex | c8781f9e7 |
53813049831 has 6 divisors (see below), whose sum is σ = 77729960880. Its totient is φ = 35875366548.
The previous prime is 53813049701. The next prime is 53813049847. The reversal of 53813049831 is 13894031835.
53813049831 is a `hidden beast` number, since 53 + 81 + 3 + 0 + 498 + 31 = 666.
It is a de Polignac number, because none of the positive numbers 2k-53813049831 is a prime.
It is a super-2 number, since 2×538130498312 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53813049431) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2989613871 + ... + 2989613888.
It is an arithmetic number, because the mean of its divisors is an integer number (12954993480).
Almost surely, 253813049831 is an apocalyptic number.
53813049831 is a deficient number, since it is larger than the sum of its proper divisors (23916911049).
53813049831 is a wasteful number, since it uses less digits than its factorization.
53813049831 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5979227765 (or 5979227762 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 45.
The spelling of 53813049831 in words is "fifty-three billion, eight hundred thirteen million, forty-nine thousand, eight hundred thirty-one".
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