Base | Representation |
---|---|
bin | 110010001010010101… |
… | …000011001100110101 |
3 | 12011000121210212111012 |
4 | 302022111003030311 |
5 | 1340301224201433 |
6 | 40424302522005 |
7 | 3614465455202 |
oct | 621225031465 |
9 | 164017725435 |
10 | 53860381493 |
11 | 20929865886 |
12 | a531896305 |
13 | 5104788929 |
14 | 286d2dcca9 |
15 | 160373b848 |
hex | c8a543335 |
53860381493 has 2 divisors, whose sum is σ = 53860381494. Its totient is φ = 53860381492.
The previous prime is 53860381469. The next prime is 53860381507. The reversal of 53860381493 is 39418306835.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36965061169 + 16895320324 = 192263^2 + 129982^2 .
It is a cyclic number.
It is not a de Polignac number, because 53860381493 - 218 = 53860119349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53860381433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26930190746 + 26930190747.
It is an arithmetic number, because the mean of its divisors is an integer number (26930190747).
Almost surely, 253860381493 is an apocalyptic number.
It is an amenable number.
53860381493 is a deficient number, since it is larger than the sum of its proper divisors (1).
53860381493 is an equidigital number, since it uses as much as digits as its factorization.
53860381493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 50.
The spelling of 53860381493 in words is "fifty-three billion, eight hundred sixty million, three hundred eighty-one thousand, four hundred ninety-three".
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