Base | Representation |
---|---|
bin | 100111001101001011100… |
… | …0111111000100001010101 |
3 | 201002010110120011212102101 |
4 | 1032122113013320201111 |
5 | 1201240443122242232 |
6 | 15243224043442101 |
7 | 1064205115546636 |
oct | 116322707704125 |
9 | 21063416155371 |
10 | 5388424415317 |
11 | 1798244119849 |
12 | 730390526331 |
13 | 30118447a3c8 |
14 | 148b3044988d |
15 | 95272c821e7 |
hex | 4e6971f8855 |
5388424415317 has 4 divisors (see below), whose sum is σ = 5393551366336. Its totient is φ = 5383297464300.
The previous prime is 5388424415293. The next prime is 5388424415329. The reversal of 5388424415317 is 7135144248835.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5388424415317 - 27 = 5388424415189 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5388424415117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2563473933 + ... + 2563476034.
It is an arithmetic number, because the mean of its divisors is an integer number (1348387841584).
Almost surely, 25388424415317 is an apocalyptic number.
It is an amenable number.
5388424415317 is a deficient number, since it is larger than the sum of its proper divisors (5126951019).
5388424415317 is a wasteful number, since it uses less digits than its factorization.
5388424415317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5126951018.
The product of its digits is 12902400, while the sum is 55.
The spelling of 5388424415317 in words is "five trillion, three hundred eighty-eight billion, four hundred twenty-four million, four hundred fifteen thousand, three hundred seventeen".
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