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53902644441 = 317967548147
BaseRepresentation
bin110010001100110110…
…010001010011011001
312011010120100001100120
4302030312101103121
51340343034110231
640432412423453
73615520626612
oct621466212331
9164116301316
1053902644441
1120950701638
12a543a77b89
1351104654a9
142874b80c09
1516072d8d96
hexc8cd914d9

53902644441 has 4 divisors (see below), whose sum is σ = 71870192592. Its totient is φ = 35935096292.

The previous prime is 53902644401. The next prime is 53902644463. The reversal of 53902644441 is 14444620935.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53902644441 - 29 = 53902643929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53902644393 and 53902644402.

It is not an unprimeable number, because it can be changed into a prime (53902644401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8983774071 + ... + 8983774076.

It is an arithmetic number, because the mean of its divisors is an integer number (17967548148).

Almost surely, 253902644441 is an apocalyptic number.

It is an amenable number.

53902644441 is a deficient number, since it is larger than the sum of its proper divisors (17967548151).

53902644441 is a wasteful number, since it uses less digits than its factorization.

53902644441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17967548150.

The product of its (nonzero) digits is 414720, while the sum is 42.

The spelling of 53902644441 in words is "fifty-three billion, nine hundred two million, six hundred forty-four thousand, four hundred forty-one".

Divisors: 1 3 17967548147 53902644441