Base | Representation |
---|---|
bin | 110010001100111110… |
… | …010111110010001111 |
3 | 12011010201022221112012 |
4 | 302030332113302033 |
5 | 1340344110040033 |
6 | 40432530131435 |
7 | 3615544653302 |
oct | 621476276217 |
9 | 164121287465 |
10 | 53904768143 |
11 | 20951922166 |
12 | a544720b7b |
13 | 5110a2a015 |
14 | 2875174b39 |
15 | 16075a8248 |
hex | c8cf97c8f |
53904768143 has 4 divisors (see below), whose sum is σ = 53906609280. Its totient is φ = 53902927008.
The previous prime is 53904768131. The next prime is 53904768149. The reversal of 53904768143 is 34186740935.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53904768143 - 214 = 53904751759 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53904768091 and 53904768100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53904768149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 875930 + ... + 935447.
It is an arithmetic number, because the mean of its divisors is an integer number (13476652320).
Almost surely, 253904768143 is an apocalyptic number.
53904768143 is a deficient number, since it is larger than the sum of its proper divisors (1841137).
53904768143 is a wasteful number, since it uses less digits than its factorization.
53904768143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1841136.
The product of its (nonzero) digits is 2177280, while the sum is 50.
The spelling of 53904768143 in words is "fifty-three billion, nine hundred four million, seven hundred sixty-eight thousand, one hundred forty-three".
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