Base | Representation |
---|---|
bin | 100111001110001010000… |
… | …1000100001001111110101 |
3 | 201002022212201122200222001 |
4 | 1032130110020201033311 |
5 | 1201304242030443013 |
6 | 15244212124335301 |
7 | 1064311103506024 |
oct | 116342410411765 |
9 | 21068781580861 |
10 | 5390521734133 |
11 | 179911aa96488 |
12 | 7308769a4531 |
13 | 301429b39a63 |
14 | 148c8cbd88bb |
15 | 95346e69ddd |
hex | 4e7142213f5 |
5390521734133 has 2 divisors, whose sum is σ = 5390521734134. Its totient is φ = 5390521734132.
The previous prime is 5390521733977. The next prime is 5390521734211. The reversal of 5390521734133 is 3314371250935.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5090154162769 + 300367571364 = 2256137^2 + 548058^2 .
It is a cyclic number.
It is not a de Polignac number, because 5390521734133 - 225 = 5390488179701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5390521714133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2695260867066 + 2695260867067.
It is an arithmetic number, because the mean of its divisors is an integer number (2695260867067).
Almost surely, 25390521734133 is an apocalyptic number.
It is an amenable number.
5390521734133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5390521734133 is an equidigital number, since it uses as much as digits as its factorization.
5390521734133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1020600, while the sum is 46.
The spelling of 5390521734133 in words is "five trillion, three hundred ninety billion, five hundred twenty-one million, seven hundred thirty-four thousand, one hundred thirty-three".
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